A tuning fork A of frequency 200 Hz is sounded with fork B, the number of beats per second is 5. By putting some wax on A, the number of beats increases to 8. The frequency of fork B is
Text Solution
Verified by ExpertsThe correct answer is:
D
n A ↓ ↓ – n B = x ... (i) Wrong
n B – n A ↓ ↓ = x ... (ii) Correct
⇒ ⇒ n B = n A + x = 200 + 5 = 205 Hz.
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